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This has been bounced around for a couple years now #474 and a few others have expressed desire to work with non-standard option names. We have been somewhat resistant to that but I think it can be done now. This PR adds a modifier `allow_non_standard_option_names()` It is purposely long, it is purposely off by default. But what it does is allow option names with a single `-` to act like a short option name. With this modifier enabled no single letter short option names are allowed to start with the same letter as a non-standard names. For example `-s` and `-single` would not be allowed. --------- Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com> Co-authored-by: Henry Schreiner <HenrySchreinerIII@gmail.com>
53 lines
1.5 KiB
C++
53 lines
1.5 KiB
C++
// Copyright (c) 2017-2024, University of Cincinnati, developed by Henry Schreiner
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// under NSF AWARD 1414736 and by the respective contributors.
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// All rights reserved.
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//
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// SPDX-License-Identifier: BSD-3-Clause
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#include <CLI/CLI.hpp>
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#include <algorithm>
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#include <iostream>
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#include <string>
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#include <tuple>
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#include <vector>
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int main(int argc, char **argv) {
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CLI::App app{"An app to practice mixing unlimited arguments, but still recover the original order."};
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std::vector<int> foos;
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auto *foo = app.add_option("--foo,-f", foos, "Some unlimited argument");
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std::vector<int> bars;
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auto *bar = app.add_option("--bar", bars, "Some unlimited argument");
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app.add_flag("--z,--x", "Random other flags");
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// Standard parsing lines (copy and paste in, or use CLI11_PARSE)
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try {
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app.parse(argc, argv);
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} catch(const CLI::ParseError &e) {
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return app.exit(e);
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}
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// I prefer using the back and popping
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std::reverse(std::begin(foos), std::end(foos));
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std::reverse(std::begin(bars), std::end(bars));
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std::vector<std::pair<std::string, int>> keyval;
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for(auto *option : app.parse_order()) {
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if(option == foo) {
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keyval.emplace_back("foo", foos.back());
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foos.pop_back();
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}
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if(option == bar) {
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keyval.emplace_back("bar", bars.back());
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bars.pop_back();
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}
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}
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// Prove the vector is correct
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for(auto &pair : keyval) {
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std::cout << pair.first << " : " << pair.second << '\n';
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}
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}
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