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Rename detail to lambda2_detail, because using namespace boost::lambda2 makes it visible

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This commit is contained in:
Peter Dimov 2021-06-27 03:49:57 +03:00
parent e0793208a1
commit 1424e6ea62
1 changed files with 4 additions and 4 deletions
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8
include/boost/lambda2/lambda2.hpp
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@ -18,7 +18,7 @@ namespace boost
namespace lambda2
{
namespace detail
namespace lambda2_detail
{
template<class T> using remove_cvref_t = std::remove_cv_t<std::remove_reference_t<T>>;
@ -32,17 +32,17 @@ template<class A> using enable_unary_lambda =
template<class A, class B> using enable_binary_lambda =
std::enable_if_t<is_lambda_expression<A>::value || is_lambda_expression<B>::value>;
} // namespace detail
} // namespace lambda2_detail
#define BOOST_LAMBDA2_UNARY_LAMBDA(op, fn) \
template<class A, class = detail::enable_unary_lambda<A>> \
template<class A, class = lambda2_detail::enable_unary_lambda<A>> \
auto operator op( A&& a ) \
{ \
return std::bind( fn(), std::forward<A>(a) ); \
}
#define BOOST_LAMBDA2_BINARY_LAMBDA(op, fn) \
template<class A, class B, class = detail::enable_binary_lambda<A, B>> \
template<class A, class B, class = lambda2_detail::enable_binary_lambda<A, B>> \
auto operator op( A&& a, B&& b ) \
{ \
return std::bind( fn(), std::forward<A>(a), std::forward<B>(b) ); \